C/Math/Mod
Содержание
floating-point remainder value function
<source lang="cpp">
- include <math.h>
- include <stdio.h>
int main(void) {
printf("%1.1f", fmod(10.0, 3.0)); return 0;
}
</source>
Mod and divide
<source lang="cpp">
- include <stdio.h>
int main(void) {
printf("%d", 7/2); printf(" %d", 7%2); printf(" %d", 4/2); printf(" %d", 4%2); return 0;
}
</source>
Return remainder of floating point division: fmod
<source lang="cpp">
- include <stdio.h>
- include <math.h>
int main () {
printf ("fmod of 6.3 / 2 is %lf\n", fmod (6.3,2) ); printf ("fmod of 19.5 / 4.2 is %lf\n", fmod (19.5,4.2) ); return 0;
}
</source>
Split floating-point value into fractional and integer parts: how to use modf
<source lang="cpp">
- include <stdio.h>
- include <math.h>
int main () {
double p, fractpart, intpart; p = 3.14159265; fractpart = modf (p , &intpart); printf ("%lf = %lf + %lf \n", p, intpart, fractpart); return 0;
}
</source>
Use the mod % operator
<source lang="cpp">
- include <stdio.h>
int main(void) {
int i; printf("Enter a number: "); scanf("%d", &i); if( ( i % 2 ) == 0) printf("Even"); if( ( i % 2 ) ==1) printf("Odd"); return 0;
}
</source>