C/Math/Mod

floating-point remainder value function

<source lang="cpp">

1. include <math.h>
2. include <stdio.h>

int main(void) {

 printf("%1.1f", fmod(10.0, 3.0));
 return 0;

}

      </source>

Mod and divide

<source lang="cpp">

1. include <stdio.h>

int main(void) {

 printf("%d", 7/2);
 printf(" %d", 7%2);
 printf(" %d", 4/2);
 printf(" %d", 4%2);
 return 0;

}

      </source>

Return remainder of floating point division: fmod

<source lang="cpp">

1. include <stdio.h>
2. include <math.h>

int main () {

 printf ("fmod of 6.3 / 2 is %lf\n", fmod (6.3,2) );
 printf ("fmod of 19.5 / 4.2 is %lf\n", fmod (19.5,4.2) );
 return 0;

}

      </source>

Split floating-point value into fractional and integer parts: how to use modf

<source lang="cpp">

1. include <stdio.h>
2. include <math.h>

int main () {

 double p, fractpart, intpart;
 p = 3.14159265;
 
 fractpart = modf (p , &intpart);
 
 printf ("%lf = %lf + %lf \n", p, intpart, fractpart);
 
 return 0;

}

      </source>

Use the mod % operator

<source lang="cpp">

1. include <stdio.h>

int main(void) {

 int i;
 printf("Enter a number: ");
 scanf("%d", &i);
 
 if( ( i % 2 ) == 0) 
     printf("Even");
 if( ( i % 2 ) ==1) 
     printf("Odd");
 return 0;

}

      </source>