C++ Tutorial/Function/function prototype

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Returning a pointer from function

#include <iostream>
#include <string>
#include <vector>
using namespace std;
string* ptrToElement(vector<string>* const pVec, int i);
int main()
{
    vector<string> i;
    i.push_back("A");
    i.push_back("B");
    i.push_back("C");
    cout << *(ptrToElement(&i, 0)) << "\n\n";
    string* pStr = ptrToElement(&i, 1);
    cout << *pStr << "\n\n";
    string str = *(ptrToElement(&i, 2));
    cout << str << "\n\n";
    *pStr = "test";
    cout << i[1] << endl;
    return 0;
}
string* ptrToElement(vector<string>* const pVec, int i)
{
    return &((*pVec)[i]);
}

Use a function prototype to enforce strong type checking

#include <iostream> 
#include <cstdlib> 
using namespace std; 

void f(int i); // prototype 
 
int main() 
{ 
  int x = 10;   
  f(x);
 
  return 0; 
} 
 
void f(int i) 
{ 
  i = i * i;  
  cout << i;
}
100

Use a function"s definition as its prototype, appears before main

#include <iostream> 
using namespace std; 
  
bool isEven(int num) {  
  if(!(num )) 
      return true; 
  return false;  
}  
  
int main()  
{  
  if(isEven(4)) 
      cout << "4 is even\n";  
  if(isEven(3)) 
      cout << "this won"t display";  
  
  return 0;  
}
4 is even