C++/String/string concatenation

Concatenate Using STL string

<source lang="cpp">

1. include <string>
2. include <iostream>

int main () {

  using namespace std;
  string strSample1 ("Hello");
  string strSample2 (" String!");
  // Concatenate
  strSample1 += strSample2;
  cout << strSample1 << endl << endl;
  string strSample3 (" this is a test");
  strSample1.append (strSample3);
  cout << strSample1 << endl << endl;
  const char* charPointer = "another test";
  strSample1.append (charPointer);
  cout << strSample1 << endl;
  return 0;

}

 </source>

Concatenating Strings

<source lang="cpp">

1. include <iostream>
2. include <string>

using namespace std; int main(){

  string s1( "A " );
  string s1_original( s1 ); 
  string s2( "B " );
  cout << "String 1: " << s1 << endl << "String 2: " << s2;
  s1 += s2; 
  cout << s1;
  s1 = s1_original;
  cout << "String 1: " << s1 << "\nString 2: " << s2;
  s1 += s2.substr( 0, 18 );
  cout << s1;

}

 </source>

overloaded string concatenation operator

<source lang="cpp">

1. include <iostream>

using std::cout; using std::endl;

1. include <string>

using std::string; int main() {

  string s1( "AA" );
  string s2( " AAB" );
  string s3;
  // 
  cout << "\n\ns1 += s2 yields s1 = ";
  s1 += s2; // test overloaded concatenation
  cout << s1;
  return 0;

} /*

s1 += s2 yields s1 = AA AAB

*/        
   
 </source>

overloaded string concatenation operator with C-style string

<source lang="cpp">

1. include <iostream>

using std::cout; using std::endl;

1. include <string>

using std::string; int main() {

  string s1( "AA" );
  string s2( " AAB" );
  string s3;
  // 
  cout << "\n\ns1 += \" to you\" yields" << endl;
  s1 += " to you";  
  cout << "s1 = " << s1 << "\n\n";
  return 0;

} /*

s1 += " to you" yields s1 = AA to you

*/        
   
 </source>