C++/Data Type/Char Array

Char array and char pointer

<source lang="cpp">

1. include <iostream>

using namespace std; int main(void){

  char *array = new char[256];
  char *target, *destination;
  
  int i;
  target = new char[256];
  for (i = 0; i < 256; i++) {
    array[i] = "A";
    target[i] = "B";
  }
  destination = new char[256];
  for (i = 0; i < 256; i++) {
    destination[i] = target[i];
    cout << destination[i] << " ";
  }

}

 </source>

use char array as string

<source lang="cpp">

1. include <stdio.h>

int main( ) {

char        szmode1[4],             /* car   */
            szmode2[6];             /* plane */
static char szmode3[5] = "ship";    /* ship  */
szmode1[0] = "c";
szmode1[1] = "a";
szmode1[2] = "r";
szmode1[3] = "\0";
printf("\n\n\tPlease enter the mode �> plane ");
scanf("%s",szmode2);
printf("%s\n",szmode1);
printf("%s\n",szmode2);
printf("%s\n",szmode3);
return(0);

}

 </source>

Use cin.getline to read a char array based string

<source lang="cpp">

1. include <iostream>

using namespace std; int main() {

char name[25];
cout << "Please enter your name \n";
cin.getline(name,25);
cout << "Hello " << name << endl;
return 0;

}

 </source>

use getline to read char array based string

<source lang="cpp">

1. include <iostream>
2. include <string >

using std::cout; using std::cin;

int main() {

 char s1[40],s2[40],s3[40];
 int size;
 cout << "Please enter a word \n";
 cin.getline(s1,40); 
 cout << "Please enter another word  \n";
 cin.getline(s2,40);
 size = strlen(s1);
    
 strcat(s1,s2);
 cout << "The length of the first string you entered is" << size << "\n";
 cout << "Both strings you entered are " << s3<< "\n";
 return 0;

}

 </source>

Use new operator to allocate memory for char array

<source lang="cpp">

1. include <iostream>

using namespace std; int main(void) {

  char *pointer;
  do {
    pointer = new char[10000];
    if (pointer)
      cout << "Allocated 10,000 bytes\n";
    else
      cout << "Allocation failed\n";
  } while (pointer);

}

 </source>