C++ Tutorial/Operators statements/Operators

Demonstrates built-in arithmetic operators

<source lang="cpp">#include <iostream> using namespace std; int main() {

     cout << "7 + 3 = " << 7 + 3 << endl;
     cout << "7 - 3 = " << 7 - 3 << endl;
     cout << "7 * 3 = " << 7 * 3 << endl;
     cout << "7 / 3 = " << 7 / 3 << endl;
     cout << "7.0 / 3.0 = " << 7.0 / 3.0 << endl;
     cout << "7 % 3 = " << 7 % 3 << endl;
     cout << "7 + 3 * 5 = " << 7 + 3 * 5 << endl;
     cout << "(7 + 3) * 5 = " << (7 + 3) * 5 << endl;
     return 0;

}</source>

Demonstrating operators .* and ->*.

<source lang="cpp">#include <iostream> using std::cout; using std::endl; class MyClass { public:

  void myFunction()
  {
     cout << "In myFunction function\n";
  }
  int value;

}; void f( MyClass * ); void f2( MyClass * ); int main() {

  MyClass myFunction;
  myFunction.value = 8;
  f( &myFunction );
  f2( &myFunction );
  return 0;

} void f( MyClass *myFunctionPtr ) {

  void ( MyClass::*memPtr )() = &MyClass::myFunction;
  ( myFunctionPtr->*memPtr )();

} void f2( MyClass *myFunctionPtr2 ) {

  int MyClass::*vPtr = &MyClass::value;
  cout << ( *myFunctionPtr2 ).*vPtr << endl;

}</source>

In myFunction function
8

Precedence of C Operators

<source lang="cpp">Highest ( ) [ ] - >

           ! ~ ++ -- - (type)  * & sizeof   
           * / %   
           + -   
           <<  >>   
           < <= > >=   
           == !=   
           &   
           ^   
           |   
           &&   
           ||   
           ?   
           = += -= *= /=   

Lowest ,</source>

Using the & and * operators

<source lang="cpp">#include <iostream> using std::cout; using std::endl; int main() {

  int a;
  int *aPtr; 
  a = 7; 
  aPtr = &a;
  cout << "The address of a is " << &a << "\nThe value of aPtr is " << aPtr;
  cout << "\n\nThe value of a is " << a << "\nThe value of *aPtr is " << *aPtr;
  cout << "\n\nShowing that * and & are inverses of " << "each other.\n&*aPtr = " << &*aPtr
     << "\n*&aPtr = " << *&aPtr << endl;
  return 0;

}</source>

The address of a is 0x22ff74
The value of aPtr is 0x22ff74
The value of a is 7
The value of *aPtr is 7
Showing that * and & are inverses of each other.
&*aPtr = 0x22ff74
*&aPtr = 0x22ff74

Using the unary scope resolution operator

<source lang="cpp">#include <iostream> using std::cout; using std::endl; int n = 7; int main() {

  double n = 10.5;
  cout << "Local double value of n = " << n
     << "\nGlobal int value of n = " << ::n << endl;
  return 0;

}</source>

Local double value of n = 10.5
Global int value of n = 7