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Материал из C\C++ эксперт
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expm1: returns the natural logarithm e raised to the arg power, minus 1( e^arg-1)
Declaration: float expm1f(float arg);
double expm1(double arg);
long double expm1l(long double arg);
#include <math.h>
#include <stdio.h>
int main(void)
{
printf("Value of e to the first: %f.", expm1f(1.0));
}
/*
Value of e to the first: 1.718282.*/