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Using the bitwise shift operators
#include <stdio.h>
void displayBits( unsigned value );
int main()
{
unsigned number1 = 960;
printf( "\nThe result of left shifting\n" );
displayBits( number1 );
printf( "8 bit positions using the " );
printf( "left shift operator << is\n" );
displayBits( number1 << 8 );
printf( "\nThe result of right shifting\n" );
displayBits( number1 );
printf( "8 bit positions using the " );
printf( "right shift operator >> is\n" );
displayBits( number1 >> 8 );
return 0;
}
void displayBits( unsigned value ) {
unsigned c;
unsigned displayMask = 1 << 31;
printf( "%7u = ", value );
for ( c = 1; c <= 32; c++ ) {
putchar( value & displayMask ? "1" : "0" );
value <<= 1;
if ( c % 8 == 0 ) {
putchar( " " );
}
}
putchar( "\n" );
}The result of left shifting
960 = 00000000 00000000 00000011 11000000
8 bit positions using the left shift operator << is
245760 = 00000000 00000011 11000000 00000000
The result of right shifting
960 = 00000000 00000000 00000011 11000000
8 bit positions using the right shift operator >> is
3 = 00000000 00000000 00000000 00000011
