C Tutorial/Pointer/Address Operator — различия между версиями
| Admin (обсуждение | вклад) м (1 версия: Импорт контента...) | Admin (обсуждение | вклад)  м (1 версия: Импорт контента...) | 
| (нет различий) | |
Текущая версия на 10:32, 25 мая 2010
Using the & and * operators
#include <stdio.h>
int main()
{
   int a;        /* a is an integer */
   int *aPtr;    /* aPtr is a pointer to an integer */
   a = 7;
   aPtr = &a;    /* aPtr set to address of a */
   printf( "The address of a is %p"
           "\nThe value of aPtr is %p", &a, aPtr );
   printf( "\n\nThe value of a is %d"   
           "\nThe value of *aPtr is %d", a, *aPtr );
   printf( "\n\nShowing that * and & are complements of "
           "each other\n&*aPtr = %p"   
           "\n*&aPtr = %p\n", &*aPtr, *&aPtr );
   return 0; 
}The address of a is 9a37c The value of aPtr is 9a37c The value of a is 7 The value of *aPtr is 7 Showing that * and & are complements of each other &*aPtr = 9a37c *&aPtr = 9a37c
