C++ Tutorial/string/string concatenation — различия между версиями
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Текущая версия на 10:30, 25 мая 2010
Содержание
Concatenate two strings
#include <iostream>
#include <string>
using namespace std;
int main()
{
string str1("A");
string str2("B");
string str3("G");
string str4;
cout << " str1: " << str1 << endl;
cout << " str2: " << str2 << endl;
cout << " str3: " << str3 << "\n\n";
// Concatenate two strings.
str4 = str1 + str3;
cout << "str4 after begin assigned st1+str3: " << str4 << "\n\n";
return 0;
}overloaded string concatenation operator
#include <iostream>
using std::cout;
using std::endl;
#include <string>
using std::string;
int main()
{
string s1( "AA" );
string s2( " AAB" );
string s3;
//
cout << "\n\ns1 += s2 yields s1 = ";
s1 += s2; // test overloaded concatenation
cout << s1;
return 0;
}s1 += s2 yields s1 = AA AAB"
overloaded string concatenation operator with C-style string
#include <iostream>
using std::cout;
using std::endl;
#include <string>
using std::string;
int main()
{
string s1( "AA" );
string s2( " AAB" );
string s3;
//
cout << "\n\ns1 += \" to you\" yields" << endl;
s1 += " to you";
cout << "s1 = " << s1 << "\n\n";
return 0;
}s1 += " to you" yields s1 = AA to you
Plus string together
#include <iostream>
#include <string>
using namespace std;
int main()
{
string sentence, words[10];
int pos = 0, old_pos = 0, nwords, i = 0;
sentence = "Eskimos have 23 ways to ";
sentence += "describe snow";
while (pos < sentence.size()) {
pos = sentence.find(" ", old_pos);
words[i++].assign(sentence, old_pos, pos - old_pos);
cout << words[i - 1] << endl; //print words
old_pos = pos + 1;
}
nwords = i;
sentence = "C++ programmers ";
for (i = 1; i < nwords -1; ++i)
sentence += words[i] + " ";
sentence += "windows";
cout << sentence << endl;
}