в 14:21, 25 мая 2010

2010-05-25T14:21:06Z

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2010-05-25T10:25:45Z

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==Concatenate Using STL string==

<source lang="cpp">
#include <string>
#include <iostream>
int main ()
{
using namespace std;
string strSample1 ("Hello");
string strSample2 (" String!");
// Concatenate
strSample1 += strSample2;
cout << strSample1 << endl << endl;
string strSample3 (" this is a test");
strSample1.append (strSample3);
cout << strSample1 << endl << endl;
const char* charPointer = "another test";
strSample1.append (charPointer);
cout << strSample1 << endl;
return 0;
}

</source>

==Concatenating Strings==

<source lang="cpp">
#include <iostream>
#include <string>
using namespace std;
int main(){
string s1( "A " );
string s1_original( s1 );
string s2( "B " );
cout << "String 1: " << s1 << endl << "String 2: " << s2;
s1 += s2;
cout << s1;
s1 = s1_original;
cout << "String 1: " << s1 << "\nString 2: " << s2;
s1 += s2.substr( 0, 18 );
cout << s1;
}

</source>

==overloaded string concatenation operator==

<source lang="cpp">

#include <iostream>
using std::cout;
using std::endl;
#include <string>
using std::string;
int main()
{
string s1( "AA" );
string s2( " AAB" );
string s3;
//
cout << "\n\ns1 += s2 yields s1 = ";
s1 += s2; // test overloaded concatenation
cout << s1;
return 0;
}
/*

s1 += s2 yields s1 = AA AAB
*/

</source>

==overloaded string concatenation operator with C-style string==

<source lang="cpp">

#include <iostream>
using std::cout;
using std::endl;
#include <string>
using std::string;
int main()
{
string s1( "AA" );
string s2( " AAB" );
string s3;
//
cout << "\n\ns1 += \" to you\" yields" << endl;
s1 += " to you";
cout << "s1 = " << s1 << "\n\n";
return 0;
}
/*

s1 += " to you" yields
s1 = AA to you

*/

</source>

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C++/String/string concatenation - История изменений

в 14:21, 25 мая 2010

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